If you are looking for a solution for Perl 5, please check out the Perl 5 tutorial.

Numerical operator can be used on the scalar values.

**tutorial/scalars/numerical_operators.p6**

#!/usr/bin/env perl6 use v6; my $x = 3; my $y = 11; my $z = $x + $y; say $z; # 14 $z = $x * $y; say $z; # 33 say $y / $x; # 3.66666666666667 $z = $y % $x; # (modulus) say $z; # 2 $z += 14; # is the same as $z = $z + 14; say $z; # 16 $z++; # is the same as $z = $z + 1; $z--; # is the same as $z = $z - 1; $z = 23 ** 2; # exponentiation say $z; # 529

The

Written by Gabor Szabo

Published on 2012-01-01

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